*单个Map创建

 Map<String, String> stringStringMap = Collections.singletonMap("reason", "同意");

• 使用匿名类初始化Map

   		List<Map<String,Object>> mapList=new ArrayList<>();
        mapList.add(new HashMap<String, Object>() {{put("min", 100);put("max", 200);}});
        mapList.add(new HashMap<String, Object>() {{put("min", 400);put("max", 800);}});
        mapList.add(new HashMap<String, Object>() {{put("min", 1000);put("max", 6000);}});

• hutool包工具

HashMap<String, String> of = MapUtil.of("1", "2");

HashMap<String, String> of1 = (HashMap<String, String>) MapUtil.of(new Pair[]{Pair.of("11", "2"), Pair.of("1", "2")});

Map<String, String> build = MapUtil.builder(new HashMap<String, String>())
       .put("key1", "value1")
       .put("key3", "value3")
       .put("key2", "value2").build();

Map<Object, Object> colorMap = MapUtil.of(new String[][] {
       {"RED", "#FF0000"},
       {"GREEN", "#00FF00"},
       {"BLUE", "#0000FF"}
});

• Guava(要提前引入Guava依赖)

  	<dependency>
	       <groupId>com.google.guava</groupId>
	         <artifactId>guava</artifactId>
	       	<version>28.1-jre</version>
    </dependency>

        Map<String, String> map3 = ImmutableMap.of("张三", "34", "李四", "24");
        // 或者
        Map<String, String> map4 = ImmutableMap.<String, String>builder()
                .put("张三", "34")
                .put("李四", "24")
                .build();

*Java 9 及以上版本

    // 使用Map.of()创建一个不可变的Map
   Map<String, String> map = Map.of("A", "k", "B", "v");

• Map.ofEntries() 方法（适用于 Java 9 及以上版本）

// 使用Map.ofEntries()创建一个不可变的Map
       Map<String, String> map = Map.ofEntries(
           Entry.of("A", "B")
       );